Exercises-2

is.symmetirc=TRUE
j=n
for (i  in 1:n)
{#for
     if(x[i]!=x[(n+1)-i])
     {
           is.symmmetric=FALSE
           break
     }
   
}#for

# Find the vector x is symmetric. The example x vector in the previous problem is not symmetric, but x=c(5,7,2,7,5) is symmetric


last.i=n%/%2
is.symmetric=TRUE
for (i in 1:last.i )
{#for
      if(x[i]!=x[(n+1)-i])
      {
            is.symmmetric=FALSE
            break
      }
   
}#for